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Light incident normally on a plane mirror attached to a galvanometer coil retraces backwards as shown in Fig. 9.29. A current in the coil produces a deflection of 3.5o of the mirror. What is the displacement of the reflected spot of light on a screen placed 1.5 m away?
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1. Given Data
- Angle of mirror deflection (θ): 3.5°
- Distance to screen (d): 1.5 m
2. Concept
When a plane mirror rotates through an angle θ, the reflected ray rotates through an angle of 2θ.
Therefore, the angle of deflection of the light spot (φ) is:
φ = 2 × θ
φ = 2 × 3.5°
φ = 7.0°
3. Calculation of Displacement
Let the displacement of the spot on the screen be x.
From the geometry of the triangle formed by the mirror, the screen, and the light ray:
tan(φ) = x / d
Rearranging to find x:
x = d × tan(φ)
Substituting the values:
- x = 1.5 × tan(7°)
- x = 1.5 × 0.1228
- x = 0.1842 m
Converting to centimeters:
x ≈ 18.4 cm
Displacement of the spot = 18.4 cm
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