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Light incident normally on a plane mirror attached to a galvanometer coil retraces backwards as shown in Fig. 9.29. A current in the coil produces a deflection of 3.5o of the mirror. What is the displacement of the reflected spot of light on a screen placed 1.5 m away?

1. Given Data

  • Angle of mirror deflection (θ): 3.5°
  • Distance to screen (d): 1.5 m

2. Concept

When a plane mirror rotates through an angle θ, the reflected ray rotates through an angle of .

Therefore, the angle of deflection of the light spot (φ) is:

φ = 2 × θ

φ = 2 × 3.5°

φ = 7.0°

3. Calculation of Displacement

Let the displacement of the spot on the screen be x.

From the geometry of the triangle formed by the mirror, the screen, and the light ray:

tan(φ) = x / d

Rearranging to find x:

x = d × tan(φ)

Substituting the values:

  • x = 1.5 × tan(7°)
  • x = 1.5 × 0.1228
  • x = 0.1842 m

Converting to centimeters:

x ≈ 18.4 cm

Displacement of the spot = 18.4 cm

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