1. Given Data

• Focal Length (f): +10 cm (Consistent with previous exercise)
• Condition for Max Power: Image formed at Near Point (D)
• Image Distance (v): -25 cm

2. Part (a): Object Distance for Max Power

To view the squares distinctly with maximum magnifying power, the image must be formed at the Least Distance of Distinct Vision (D = 25 cm).

Using the Lens Formula:

1/u = 1/v - 1/f

Substituting the values:

• 1/u = 1/(-25) - 1/10
• 1/u = -(2 + 5) / 50
• 1/u = -7 / 50
• u = -50 / 7
• u ≈ -7.14 cm

3. Part (b): Calculation of Magnification

The linear magnification (m) is given by:

m = v / u

Substituting values:

• m = (-25) / (-50/7)
• m = 25 × (7/50)
• m = 1/2 × 7
• m = 3.5

4. Part (c): Comparison with Magnifying Power

Yes, the magnification is equal to the magnifying power in this case.

Explanation:

The Magnifying Power (M) of a simple microscope when the image is at the Near Point is given by the formula:

M = 1 + D/f

M = 1 + 25/10 = 1 + 2.5 = 3.5

Since the linear magnification (m) calculated in part (b) is also 3.5, the two quantities are equal. This equality holds true only when the image is formed exactly at the Near Point (D).